16y*y-2y-3=0

Solution for 16y*y-2y-3=0 equation:

16y*y-2y-3=0

We add all the numbers together, and all the variables

-2y+16y*y-3=0

Wy multiply elements

16y^2-2y-3=0

a = 16; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·16·(-3)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*16}=\frac{-12}{32}
=-3/8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*16}=\frac{16}{32}
=1/2
$