16y+12=7(3y+1)

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Solution for 16y+12=7(3y+1) equation:



16y+12=7(3y+1)
We move all terms to the left:
16y+12-(7(3y+1))=0
We calculate terms in parentheses: -(7(3y+1)), so:
7(3y+1)
We multiply parentheses
21y+7
Back to the equation:
-(21y+7)
We get rid of parentheses
16y-21y-7+12=0
We add all the numbers together, and all the variables
-5y+5=0
We move all terms containing y to the left, all other terms to the right
-5y=-5
y=-5/-5
y=1

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