16y+3y2=35

Solution for 16y+3y2=35 equation:

16y+3y^2=35

We move all terms to the left:

16y+3y^2-(35)=0

a = 3; b = 16; c = -35;
Δ = b2-4ac
Δ = 162-4·3·(-35)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-26}{2*3}=\frac{-42}{6}
=-7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+26}{2*3}=\frac{10}{6}
=1+2/3
$