16y+40=12y-(2y+14)

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Solution for 16y+40=12y-(2y+14) equation: 



16y+40=12y-(2y+14)

We move all terms to the left:

16y+40-(12y-(2y+14))=0



We calculate terms in parentheses: -(12y-(2y+14)), so:

12y-(2y+14)

We get rid of parentheses

12y-2y-14

We add all the numbers together, and all the variables

10y-14

Back to the equation:

-(10y-14)



We get rid of parentheses

16y-10y+14+40=0

We add all the numbers together, and all the variables

6y+54=0

We move all terms containing y to the left, all other terms to the right

6y=-54

y=-54/6

y=-9

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