16y-12=4(4y-3)

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Solution for 16y-12=4(4y-3) equation: 



16y-12=4(4y-3)

We move all terms to the left:

16y-12-(4(4y-3))=0



We calculate terms in parentheses: -(4(4y-3)), so:

4(4y-3)

We multiply parentheses

16y-12

Back to the equation:

-(16y-12)



We get rid of parentheses

16y-16y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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