16y-28=4(4y-7)

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Solution for 16y-28=4(4y-7) equation: 



16y-28=4(4y-7)

We move all terms to the left:

16y-28-(4(4y-7))=0



We calculate terms in parentheses: -(4(4y-7)), so:

4(4y-7)

We multiply parentheses

16y-28

Back to the equation:

-(16y-28)



We get rid of parentheses

16y-16y+28-28=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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