16y-4(2+3y)-(-4-6y)=-4(y+4)+8y

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Solution for 16y-4(2+3y)-(-4-6y)=-4(y+4)+8y equation: 



16y-4(2+3y)-(-4-6y)=-4(y+4)+8y

We move all terms to the left:

16y-4(2+3y)-(-4-6y)-(-4(y+4)+8y)=0

We add all the numbers together, and all the variables

16y-4(3y+2)-(-6y-4)-(-4(y+4)+8y)=0

We multiply parentheses

16y-12y-(-6y-4)-(-4(y+4)+8y)-8=0

We get rid of parentheses

16y-12y+6y-(-4(y+4)+8y)+4-8=0



We calculate terms in parentheses: -(-4(y+4)+8y), so:

-4(y+4)+8y

We add all the numbers together, and all the variables

8y-4(y+4)

We multiply parentheses

8y-4y-16

We add all the numbers together, and all the variables

4y-16

Back to the equation:

-(4y-16)



We add all the numbers together, and all the variables

10y-(4y-16)-4=0

We get rid of parentheses

10y-4y+16-4=0

We add all the numbers together, and all the variables

6y+12=0

We move all terms containing y to the left, all other terms to the right

6y=-12

y=-12/6

y=-2

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