16y-8(3y-4)=48

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Solution for 16y-8(3y-4)=48 equation: 



16y-8(3y-4)=48

We move all terms to the left:

16y-8(3y-4)-(48)=0

We multiply parentheses

16y-24y+32-48=0

We add all the numbers together, and all the variables

-8y-16=0

We move all terms containing y to the left, all other terms to the right

-8y=16

y=16/-8

y=-2

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