16y2+24y=-9

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Solution for 16y2+24y=-9 equation:



16y^2+24y=-9
We move all terms to the left:
16y^2+24y-(-9)=0
We add all the numbers together, and all the variables
16y^2+24y+9=0
a = 16; b = 24; c = +9;
Δ = b2-4ac
Δ = 242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-24}{32}=-3/4$

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