16y2+8y+1=18

Solution for 16y2+8y+1=18 equation:

16y^2+8y+1=18

We move all terms to the left:

16y^2+8y+1-(18)=0

We add all the numbers together, and all the variables

16y^2+8y-17=0

a = 16; b = 8; c = -17;
Δ = b2-4ac
Δ = 82-4·16·(-17)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24\sqrt{2}}{2*16}=\frac{-8-24\sqrt{2}}{32}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24\sqrt{2}}{2*16}=\frac{-8+24\sqrt{2}}{32}
$