16y2-361=0

Solution for 16y2-361=0 equation:

16y^2-361=0

a = 16; b = 0; c = -361;
Δ = b2-4ac
Δ = 02-4·16·(-361)
Δ = 23104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23104}=152$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-152}{2*16}=\frac{-152}{32}
=-4+3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+152}{2*16}=\frac{152}{32}
=4+3/4
$