16y2-8y-120=0

Solution for 16y2-8y-120=0 equation:

16y^2-8y-120=0

a = 16; b = -8; c = -120;
Δ = b2-4ac
Δ = -82-4·16·(-120)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-88}{2*16}=\frac{-80}{32}
=-2+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+88}{2*16}=\frac{96}{32}
=3
$