17(3d-4)+100=66

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Solution for 17(3d-4)+100=66 equation: 



17(3d-4)+100=66

We move all terms to the left:

17(3d-4)+100-(66)=0

We add all the numbers together, and all the variables

17(3d-4)+34=0

We multiply parentheses

51d-68+34=0

We add all the numbers together, and all the variables

51d-34=0

We move all terms containing d to the left, all other terms to the right

51d=34

d=34/51

d=2/3

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