17(6x+20)=-30(x-2)

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Solution for 17(6x+20)=-30(x-2) equation: 



17(6x+20)=-30(x-2)

We move all terms to the left:

17(6x+20)-(-30(x-2))=0

We multiply parentheses

102x-(-30(x-2))+340=0



We calculate terms in parentheses: -(-30(x-2)), so:

-30(x-2)

We multiply parentheses

-30x+60

Back to the equation:

-(-30x+60)



We get rid of parentheses

102x+30x-60+340=0

We add all the numbers together, and all the variables

132x+280=0

We move all terms containing x to the left, all other terms to the right

132x=-280

x=-280/132

x=-2+4/33

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