17(6x+20)=-30(x-2)

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Solution for 17(6x+20)=-30(x-2) equation:



17(6x+20)=-30(x-2)
We move all terms to the left:
17(6x+20)-(-30(x-2))=0
We multiply parentheses
102x-(-30(x-2))+340=0
We calculate terms in parentheses: -(-30(x-2)), so:
-30(x-2)
We multiply parentheses
-30x+60
Back to the equation:
-(-30x+60)
We get rid of parentheses
102x+30x-60+340=0
We add all the numbers together, and all the variables
132x+280=0
We move all terms containing x to the left, all other terms to the right
132x=-280
x=-280/132
x=-2+4/33

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