17(t-2)+4t=7(3t+3)-10

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Solution for 17(t-2)+4t=7(3t+3)-10 equation:


Simplifying
17(t + -2) + 4t = 7(3t + 3) + -10

Reorder the terms:
17(-2 + t) + 4t = 7(3t + 3) + -10
(-2 * 17 + t * 17) + 4t = 7(3t + 3) + -10
(-34 + 17t) + 4t = 7(3t + 3) + -10

Combine like terms: 17t + 4t = 21t
-34 + 21t = 7(3t + 3) + -10

Reorder the terms:
-34 + 21t = 7(3 + 3t) + -10
-34 + 21t = (3 * 7 + 3t * 7) + -10
-34 + 21t = (21 + 21t) + -10

Reorder the terms:
-34 + 21t = 21 + -10 + 21t

Combine like terms: 21 + -10 = 11
-34 + 21t = 11 + 21t

Add '-21t' to each side of the equation.
-34 + 21t + -21t = 11 + 21t + -21t

Combine like terms: 21t + -21t = 0
-34 + 0 = 11 + 21t + -21t
-34 = 11 + 21t + -21t

Combine like terms: 21t + -21t = 0
-34 = 11 + 0
-34 = 11

Solving
-34 = 11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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