17(t-3)+4t=7(3t+2)-10

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Solution for 17(t-3)+4t=7(3t+2)-10 equation: 



17(t-3)+4t=7(3t+2)-10

We move all terms to the left:

17(t-3)+4t-(7(3t+2)-10)=0

We add all the numbers together, and all the variables

4t+17(t-3)-(7(3t+2)-10)=0

We multiply parentheses

4t+17t-(7(3t+2)-10)-51=0



We calculate terms in parentheses: -(7(3t+2)-10), so:

7(3t+2)-10

We multiply parentheses

21t+14-10

We add all the numbers together, and all the variables

21t+4

Back to the equation:

-(21t+4)



We add all the numbers together, and all the variables

21t-(21t+4)-51=0

We get rid of parentheses

21t-21t-4-51=0

We add all the numbers together, and all the variables

-55!=0

There is no solution for this equation

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