17(x-3)(x+3)=360

Solution for 17(x-3)(x+3)=360 equation:

17(x-3)(x+3)=360

We move all terms to the left:

17(x-3)(x+3)-(360)=0

We use the square of the difference formula

x^2-9-360=0

We add all the numbers together, and all the variables

x^2-369=0

a = 1; b = 0; c = -369;
Δ = b2-4ac
Δ = 02-4·1·(-369)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{41}}{2*1}=\frac{0-6\sqrt{41}}{2}
=-\frac{6\sqrt{41}}{2}
=-3\sqrt{41}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{41}}{2*1}=\frac{0+6\sqrt{41}}{2}
=\frac{6\sqrt{41}}{2}
=3\sqrt{41}
$