17*(6x-50)=204*(7/25*x)

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Solution for 17*(6x-50)=204*(7/25*x) equation: 



17(6x-50)=204(7/25x)

We move all terms to the left:

17(6x-50)-(204(7/25x))=0



Domain of the equation: 25x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

17(6x-50)-(204(+7/25x))=0

We multiply parentheses

102x-(204(+7/25x))-850=0

We multiply all the terms by the denominator


102x*25x))-(204(-850*25x))+7=0

Wy multiply elements

2550x^2-21250x=0

a = 2550; b = -21250; c = 0;
Δ = b2-4ac
Δ = -212502-4·2550·0
Δ = 451562500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{451562500}=21250$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21250)-21250}{2*2550}=\frac{0}{5100}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21250)+21250}{2*2550}=\frac{42500}{5100}
=8+1/3
$

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