17+3(15-c)=(4-c)-2(c-5)

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Solution for 17+3(15-c)=(4-c)-2(c-5) equation: 



17+3(15-c)=(4-c)-2(c-5)

We move all terms to the left:

17+3(15-c)-((4-c)-2(c-5))=0

We add all the numbers together, and all the variables

3(-1c+15)-((-1c+4)-2(c-5))+17=0

We multiply parentheses

-3c-((-1c+4)-2(c-5))+45+17=0



We calculate terms in parentheses: -((-1c+4)-2(c-5)), so:

(-1c+4)-2(c-5)

We multiply parentheses

(-1c+4)-2c+10

We get rid of parentheses

-1c-2c+4+10

We add all the numbers together, and all the variables

-3c+14

Back to the equation:

-(-3c+14)



We add all the numbers together, and all the variables

-3c-(-3c+14)+62=0

We get rid of parentheses

-3c+3c-14+62=0

We add all the numbers together, and all the variables

48!=0

There is no solution for this equation

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