17+3(z-2)=-7(z+2)+14

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Solution for 17+3(z-2)=-7(z+2)+14 equation: 



17+3(z-2)=-7(z+2)+14

We move all terms to the left:

17+3(z-2)-(-7(z+2)+14)=0

We multiply parentheses

3z-(-7(z+2)+14)-6+17=0



We calculate terms in parentheses: -(-7(z+2)+14), so:

-7(z+2)+14

We multiply parentheses

-7z-14+14

We add all the numbers together, and all the variables

-7z

Back to the equation:

-(-7z)



We add all the numbers together, and all the variables

3z-(-7z)+11=0

We get rid of parentheses

3z+7z+11=0

We add all the numbers together, and all the variables

10z+11=0

We move all terms containing z to the left, all other terms to the right

10z=-11

z=-11/10

z=-1+1/10

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