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17+4h^2=1-5h
We move all terms to the left:
17+4h^2-(1-5h)=0
We add all the numbers together, and all the variables
4h^2-(-5h+1)+17=0
We get rid of parentheses
4h^2+5h-1+17=0
We add all the numbers together, and all the variables
4h^2+5h+16=0
a = 4; b = 5; c = +16;
Δ = b2-4ac
Δ = 52-4·4·16
Δ = -231
Delta is less than zero, so there is no solution for the equation
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