17-(4y-5)/2=12-5y

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Solution for 17-(4y-5)/2=12-5y equation:



17-(4y-5)/2=12-5y
We move all terms to the left:
17-(4y-5)/2-(12-5y)=0
We add all the numbers together, and all the variables
-(4y-5)/2-(-5y+12)+17=0
We get rid of parentheses
-(4y-5)/2+5y-12+17=0
We multiply all the terms by the denominator
-(4y-5)+5y*2-12*2+17*2=0
We add all the numbers together, and all the variables
-(4y-5)+5y*2+10=0
Wy multiply elements
-(4y-5)+10y+10=0
We get rid of parentheses
-4y+10y+5+10=0
We add all the numbers together, and all the variables
6y+15=0
We move all terms containing y to the left, all other terms to the right
6y=-15
y=-15/6
y=-2+1/2

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