17-(x-14)=3(x+2)+1

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Solution for 17-(x-14)=3(x+2)+1 equation: 



17-(x-14)=3(x+2)+1

We move all terms to the left:

17-(x-14)-(3(x+2)+1)=0

We get rid of parentheses

-x-(3(x+2)+1)+14+17=0



We calculate terms in parentheses: -(3(x+2)+1), so:

3(x+2)+1

We multiply parentheses

3x+6+1

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

-1x-(3x+7)+31=0

We get rid of parentheses

-1x-3x-7+31=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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