17-1/3(6z+24)=-3z-11

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Solution for 17-1/3(6z+24)=-3z-11 equation: 



17-1/3(6z+24)=-3z-11

We move all terms to the left:

17-1/3(6z+24)-(-3z-11)=0



Domain of the equation: 3(6z+24)!=0

z∈R



We get rid of parentheses

-1/3(6z+24)+3z+11+17=0

We multiply all the terms by the denominator


3z*3(6z+24)+11*3(6z+24)+17*3(6z+24)-1=0

Wy multiply elements

9z^2(6+33z(6+51z(6-1=0

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