17-2b=-3(b-5)+8

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Solution for 17-2b=-3(b-5)+8 equation:



17-2b=-3(b-5)+8
We move all terms to the left:
17-2b-(-3(b-5)+8)=0
We calculate terms in parentheses: -(-3(b-5)+8), so:
-3(b-5)+8
We multiply parentheses
-3b+15+8
We add all the numbers together, and all the variables
-3b+23
Back to the equation:
-(-3b+23)
We get rid of parentheses
-2b+3b-23+17=0
We add all the numbers together, and all the variables
b-6=0
We move all terms containing b to the left, all other terms to the right
b=6

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