17-3x/(x-3)(x-4)=x+1/x-4

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Solution for 17-3x/(x-3)(x-4)=x+1/x-4 equation: 



17-3x/(x-3)(x-4)=x+1/x-4

We move all terms to the left:

17-3x/(x-3)(x-4)-(x+1/x-4)=0



Domain of the equation: (x-3)(x-4)!=0

We move all terms containing x to the left, all other terms to the right

x-3)(x!=4

x∈R





Domain of the equation: x-4)!=0

x∈R



We get rid of parentheses

-3x/(x-3)(x-4)-x-1/x+4+17=0

We multiply parentheses ..

-3x/(+x^2-4x-3x+12)-x-1/x+4+17=0

We calculate fractions

We do not support expression: x^3

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