17-5(y-2)=45y+8(2y-3)-39y

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Solution for 17-5(y-2)=45y+8(2y-3)-39y equation: 



17-5(y-2)=45y+8(2y-3)-39y

We move all terms to the left:

17-5(y-2)-(45y+8(2y-3)-39y)=0

We multiply parentheses

-5y-(45y+8(2y-3)-39y)+10+17=0



We calculate terms in parentheses: -(45y+8(2y-3)-39y), so:

45y+8(2y-3)-39y

We add all the numbers together, and all the variables

6y+8(2y-3)

We multiply parentheses

6y+16y-24

We add all the numbers together, and all the variables

22y-24

Back to the equation:

-(22y-24)



We add all the numbers together, and all the variables

-5y-(22y-24)+27=0

We get rid of parentheses

-5y-22y+24+27=0

We add all the numbers together, and all the variables

-27y+51=0

We move all terms containing y to the left, all other terms to the right

-27y=-51

y=-51/-27

y=1+8/9

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