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17-x2+16x=0
We add all the numbers together, and all the variables
-1x^2+16x+17=0
a = -1; b = 16; c = +17;
Δ = b2-4ac
Δ = 162-4·(-1)·17
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-18}{2*-1}=\frac{-34}{-2} =+17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+18}{2*-1}=\frac{2}{-2} =-1 $
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