17/2m-3/m=1

Solution for 17/2m-3/m=1 equation:

17/2m-3/m=1

We move all terms to the left:

17/2m-3/m-(1)=0


Domain of the equation: 2m!=0

m!=0/2

m!=0

m∈R



Domain of the equation: m!=0

m∈R


We calculate fractions


17m/2m^2+(-6m)/2m^2-1=0

We multiply all the terms by the denominator


17m+(-6m)-1*2m^2=0

Wy multiply elements

-2m^2+17m+(-6m)=0

We get rid of parentheses

-2m^2+17m-6m=0

We add all the numbers together, and all the variables

-2m^2+11m=0

a = -2; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-2)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-2}=\frac{-22}{-4}
=5+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-2}=\frac{0}{-4}
=0
$