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170=(2w-3)w
We move all terms to the left:
170-((2w-3)w)=0
We calculate terms in parentheses: -((2w-3)w), so:We get rid of parentheses
(2w-3)w
We multiply parentheses
2w^2-3w
Back to the equation:
-(2w^2-3w)
-2w^2+3w+170=0
a = -2; b = 3; c = +170;
Δ = b2-4ac
Δ = 32-4·(-2)·170
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-37}{2*-2}=\frac{-40}{-4} =+10 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+37}{2*-2}=\frac{34}{-4} =-8+1/2 $
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