170=(2x+10)X

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Solution for 170=(2x+10)X equation:



170=(2x+10)x
We move all terms to the left:
170-((2x+10)x)=0
We calculate terms in parentheses: -((2x+10)x), so:
(2x+10)x
We multiply parentheses
2x^2+10x
Back to the equation:
-(2x^2+10x)
We get rid of parentheses
-2x^2-10x+170=0
a = -2; b = -10; c = +170;
Δ = b2-4ac
Δ = -102-4·(-2)·170
Δ = 1460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1460}=\sqrt{4*365}=\sqrt{4}*\sqrt{365}=2\sqrt{365}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{365}}{2*-2}=\frac{10-2\sqrt{365}}{-4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{365}}{2*-2}=\frac{10+2\sqrt{365}}{-4} $

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