170=(2x+10)X

Solution for 170=(2x+10)X equation:

170=(2x+10)x

We move all terms to the left:

170-((2x+10)x)=0


We calculate terms in parentheses: -((2x+10)x), so:

(2x+10)x

We multiply parentheses

2x^2+10x

Back to the equation:

-(2x^2+10x)


We get rid of parentheses

-2x^2-10x+170=0

a = -2; b = -10; c = +170;
Δ = b2-4ac
Δ = -102-4·(-2)·170
Δ = 1460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1460}=\sqrt{4*365}=\sqrt{4}*\sqrt{365}=2\sqrt{365}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{365}}{2*-2}=\frac{10-2\sqrt{365}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{365}}{2*-2}=\frac{10+2\sqrt{365}}{-4}
$