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171=(x+3)(3x)
We move all terms to the left:
171-((x+3)(3x))=0
We calculate terms in parentheses: -((x+3)3x), so:We get rid of parentheses
(x+3)3x
We multiply parentheses
3x^2+9x
Back to the equation:
-(3x^2+9x)
-3x^2-9x+171=0
a = -3; b = -9; c = +171;
Δ = b2-4ac
Δ = -92-4·(-3)·171
Δ = 2133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2133}=\sqrt{9*237}=\sqrt{9}*\sqrt{237}=3\sqrt{237}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{237}}{2*-3}=\frac{9-3\sqrt{237}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{237}}{2*-3}=\frac{9+3\sqrt{237}}{-6} $
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