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1725=m+1/2m
We move all terms to the left:
1725-(m+1/2m)=0
Domain of the equation: 2m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
-(+m+1/2m)+1725=0
We get rid of parentheses
-m-1/2m+1725=0
We multiply all the terms by the denominator
-m*2m+1725*2m-1=0
Wy multiply elements
-2m^2+3450m-1=0
a = -2; b = 3450; c = -1;
Δ = b2-4ac
Δ = 34502-4·(-2)·(-1)
Δ = 11902492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11902492}=\sqrt{196*60727}=\sqrt{196}*\sqrt{60727}=14\sqrt{60727}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3450)-14\sqrt{60727}}{2*-2}=\frac{-3450-14\sqrt{60727}}{-4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3450)+14\sqrt{60727}}{2*-2}=\frac{-3450+14\sqrt{60727}}{-4} $
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