176=(b+5)b

Solution for 176=(b+5)b equation:

176=(b+5)b

We move all terms to the left:

176-((b+5)b)=0


We calculate terms in parentheses: -((b+5)b), so:

(b+5)b

We multiply parentheses

b^2+5b

Back to the equation:

-(b^2+5b)


We get rid of parentheses

-b^2-5b+176=0

We add all the numbers together, and all the variables

-1b^2-5b+176=0

a = -1; b = -5; c = +176;
Δ = b2-4ac
Δ = -52-4·(-1)·176
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-27}{2*-1}=\frac{-22}{-2}
=+11
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+27}{2*-1}=\frac{32}{-2}
=-16
$