17=(-3+5)(4+3a)+(3-6)(a-6)

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Solution for 17=(-3+5)(4+3a)+(3-6)(a-6) equation: 



17=(-3+5)(4+3a)+(3-6)(a-6)

We move all terms to the left:

17-((-3+5)(4+3a)+(3-6)(a-6))=0

We add all the numbers together, and all the variables

-(2(3a+4)+(-3)(a-6))+17=0

We multiply parentheses ..

-(2(3a+4)+(-3a+18))+17=0



We calculate terms in parentheses: -(2(3a+4)+(-3a+18)), so:

2(3a+4)+(-3a+18)

We multiply parentheses

6a+(-3a+18)+8

We get rid of parentheses

6a-3a+18+8

We add all the numbers together, and all the variables

3a+26

Back to the equation:

-(3a+26)



We get rid of parentheses

-3a-26+17=0

We add all the numbers together, and all the variables

-3a-9=0

We move all terms containing a to the left, all other terms to the right

-3a=9

a=9/-3

a=-3

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