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17=1/3(-9p+6)
We move all terms to the left:
17-(1/3(-9p+6))=0
Domain of the equation: 3(-9p+6))!=0We multiply all the terms by the denominator
p∈R
-(1+17*3(-9p+6))=0
We calculate terms in parentheses: -(1+17*3(-9p+6)), so:
1+17*3(-9p+6)
determiningTheFunctionDomain 17*3(-9p+6)+1
Wy multiply elements
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We use the square of the difference formula
51p(-1
Back to the equation:
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| 3x5=x-11 | | p/10-4=1 | | 2/3z=44/1 | | 14.6r+5.7=-78.9 | | -5r-6=29 | | 70-4x+12x=-90 | | 15-4c=51 | | 180=2x+68 | | -4x+2x=2x+14 | | m+30/7=7 | | 80=-20+x | | 12q+6.8=23.6 | | 5x-3=13x-84 | | 95+5x+5=180 | | 19z=32 | | 8-(-4)=x | | 5x−9=56 | | h+27/7=2 | | -3(y+6)=10 | | 3(x+1)2(x+2)=2 | | -x+14=23 | | x–3.23=0.77 | | 25+3t=88 | | 3.5x+1.1=15.1 | | 9s+17=71 | | -84=6(b+41) | | 7-m/3=14 | | 3n÷2=-45 | | t/18-48=-92 | | 78=3(k-73) | | 4x=4=32 | | (y-4)=6 |