17=29(5+b)+17

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Solution for 17=29(5+b)+17 equation:



17=29(5+b)+17
We move all terms to the left:
17-(29(5+b)+17)=0
We add all the numbers together, and all the variables
-(29(b+5)+17)+17=0
We calculate terms in parentheses: -(29(b+5)+17), so:
29(b+5)+17
We multiply parentheses
29b+145+17
We add all the numbers together, and all the variables
29b+162
Back to the equation:
-(29b+162)
We get rid of parentheses
-29b-162+17=0
We add all the numbers together, and all the variables
-29b-145=0
We move all terms containing b to the left, all other terms to the right
-29b=145
b=145/-29
b=-5

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