17=3(g+4)-g

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Solution for 17=3(g+4)-g equation: 



17=3(g+4)-g

We move all terms to the left:

17-(3(g+4)-g)=0



We calculate terms in parentheses: -(3(g+4)-g), so:

3(g+4)-g

We add all the numbers together, and all the variables

-1g+3(g+4)

We multiply parentheses

-1g+3g+12

We add all the numbers together, and all the variables

2g+12

Back to the equation:

-(2g+12)



We get rid of parentheses

-2g-12+17=0

We add all the numbers together, and all the variables

-2g+5=0

We move all terms containing g to the left, all other terms to the right

-2g=-5

g=-5/-2

g=2+1/2

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