17=3(r+1)-4r

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Solution for 17=3(r+1)-4r equation: 



17=3(r+1)-4r

We move all terms to the left:

17-(3(r+1)-4r)=0



We calculate terms in parentheses: -(3(r+1)-4r), so:

3(r+1)-4r

We add all the numbers together, and all the variables

-4r+3(r+1)

We multiply parentheses

-4r+3r+3

We add all the numbers together, and all the variables

-1r+3

Back to the equation:

-(-1r+3)



We get rid of parentheses

1r-3+17=0

We add all the numbers together, and all the variables

r+14=0

We move all terms containing r to the left, all other terms to the right

r=-14

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