17=3(z-11)+5

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Solution for 17=3(z-11)+5 equation: 



17=3(z-11)+5

We move all terms to the left:

17-(3(z-11)+5)=0



We calculate terms in parentheses: -(3(z-11)+5), so:

3(z-11)+5

We multiply parentheses

3z-33+5

We add all the numbers together, and all the variables

3z-28

Back to the equation:

-(3z-28)



We get rid of parentheses

-3z+28+17=0

We add all the numbers together, and all the variables

-3z+45=0

We move all terms containing z to the left, all other terms to the right

-3z=-45

z=-45/-3

z=+15

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