17=4c+5(c-2)

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Solution for 17=4c+5(c-2) equation: 



17=4c+5(c-2)

We move all terms to the left:

17-(4c+5(c-2))=0



We calculate terms in parentheses: -(4c+5(c-2)), so:

4c+5(c-2)

We multiply parentheses

4c+5c-10

We add all the numbers together, and all the variables

9c-10

Back to the equation:

-(9c-10)



We get rid of parentheses

-9c+10+17=0

We add all the numbers together, and all the variables

-9c+27=0

We move all terms containing c to the left, all other terms to the right

-9c=-27

c=-27/-9

c=+3

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