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17=5+(2)/(3)k
We move all terms to the left:
17-(5+(2)/(3)k)=0
Domain of the equation: 3k)!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
-(2/3k+5)+17=0
We get rid of parentheses
-2/3k-5+17=0
We multiply all the terms by the denominator
-5*3k+17*3k-2=0
Wy multiply elements
-15k+51k-2=0
We add all the numbers together, and all the variables
36k-2=0
We move all terms containing k to the left, all other terms to the right
36k=2
k=2/36
k=1/18
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