17=5b-4(3b+1)

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Solution for 17=5b-4(3b+1) equation:



17=5b-4(3b+1)
We move all terms to the left:
17-(5b-4(3b+1))=0
We calculate terms in parentheses: -(5b-4(3b+1)), so:
5b-4(3b+1)
We multiply parentheses
5b-12b-4
We add all the numbers together, and all the variables
-7b-4
Back to the equation:
-(-7b-4)
We get rid of parentheses
7b+4+17=0
We add all the numbers together, and all the variables
7b+21=0
We move all terms containing b to the left, all other terms to the right
7b=-21
b=-21/7
b=-3

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