17=5b-4(3b+1)

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Solution for 17=5b-4(3b+1) equation: 



17=5b-4(3b+1)

We move all terms to the left:

17-(5b-4(3b+1))=0



We calculate terms in parentheses: -(5b-4(3b+1)), so:

5b-4(3b+1)

We multiply parentheses

5b-12b-4

We add all the numbers together, and all the variables

-7b-4

Back to the equation:

-(-7b-4)



We get rid of parentheses

7b+4+17=0

We add all the numbers together, and all the variables

7b+21=0

We move all terms containing b to the left, all other terms to the right

7b=-21

b=-21/7

b=-3

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