17=5k2

Solution for 17=5k2 equation:

17=5k^2

We move all terms to the left:

17-(5k^2)=0

a = -5; b = 0; c = +17;
Δ = b2-4ac
Δ = 02-4·(-5)·17
Δ = 340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{340}=\sqrt{4*85}=\sqrt{4}*\sqrt{85}=2\sqrt{85}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{85}}{2*-5}=\frac{0-2\sqrt{85}}{-10}
=-\frac{2\sqrt{85}}{-10}
=-\frac{\sqrt{85}}{-5}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{85}}{2*-5}=\frac{0+2\sqrt{85}}{-10}
=\frac{2\sqrt{85}}{-10}
=\frac{\sqrt{85}}{-5}
$