17=x2+8x-50

Solution for 17=x2+8x-50 equation:

17=x2+8x-50

We move all terms to the left:

17-(x2+8x-50)=0

We add all the numbers together, and all the variables

-(+x^2+8x-50)+17=0

We get rid of parentheses

-x^2-8x+50+17=0

We add all the numbers together, and all the variables

-1x^2-8x+67=0

a = -1; b = -8; c = +67;
Δ = b2-4ac
Δ = -82-4·(-1)·67
Δ = 332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{332}=\sqrt{4*83}=\sqrt{4}*\sqrt{83}=2\sqrt{83}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{83}}{2*-1}=\frac{8-2\sqrt{83}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{83}}{2*-1}=\frac{8+2\sqrt{83}}{-2}
$