17a+7-2(a-3)=4a-10

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Solution for 17a+7-2(a-3)=4a-10 equation: 



17a+7-2(a-3)=4a-10

We move all terms to the left:

17a+7-2(a-3)-(4a-10)=0

We multiply parentheses

17a-2a-(4a-10)+6+7=0

We get rid of parentheses

17a-2a-4a+10+6+7=0

We add all the numbers together, and all the variables

11a+23=0

We move all terms containing a to the left, all other terms to the right

11a=-23

a=-23/11

a=-2+1/11

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