17a-7(a+1)=4(a-2)

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Solution for 17a-7(a+1)=4(a-2) equation: 



17a-7(a+1)=4(a-2)

We move all terms to the left:

17a-7(a+1)-(4(a-2))=0

We multiply parentheses

17a-7a-(4(a-2))-7=0



We calculate terms in parentheses: -(4(a-2)), so:

4(a-2)

We multiply parentheses

4a-8

Back to the equation:

-(4a-8)



We add all the numbers together, and all the variables

10a-(4a-8)-7=0

We get rid of parentheses

10a-4a+8-7=0

We add all the numbers together, and all the variables

6a+1=0

We move all terms containing a to the left, all other terms to the right

6a=-1

a=-1/6

a=-1/6

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