17c=c+48+5c+40

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Solution for 17c=c+48+5c+40 equation: 



17c=c+48+5c+40

We move all terms to the left:

17c-(c+48+5c+40)=0

We add all the numbers together, and all the variables

17c-(6c+88)=0

We get rid of parentheses

17c-6c-88=0

We add all the numbers together, and all the variables

11c-88=0

We move all terms containing c to the left, all other terms to the right

11c=88

c=88/11

c=8

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