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17x-12=114/3x
We move all terms to the left:
17x-12-(114/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
17x-(+114/3x)-12=0
We get rid of parentheses
17x-114/3x-12=0
We multiply all the terms by the denominator
17x*3x-12*3x-114=0
Wy multiply elements
51x^2-36x-114=0
a = 51; b = -36; c = -114;
Δ = b2-4ac
Δ = -362-4·51·(-114)
Δ = 24552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24552}=\sqrt{36*682}=\sqrt{36}*\sqrt{682}=6\sqrt{682}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{682}}{2*51}=\frac{36-6\sqrt{682}}{102} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{682}}{2*51}=\frac{36+6\sqrt{682}}{102} $
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