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17x-6(x-2)=3(x+4)
We move all terms to the left:
17x-6(x-2)-(3(x+4))=0
We multiply parentheses
17x-6x-(3(x+4))+12=0
We calculate terms in parentheses: -(3(x+4)), so:We add all the numbers together, and all the variables
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
11x-(3x+12)+12=0
We get rid of parentheses
11x-3x-12+12=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0
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